What is the phase difference between two simple harmonic motions represented by `x_(1)=A"sin"(omegat+(pi)/(6))` and `x_(2)=A "cos"omegat`?

Options

A. `(pi)/(6)`
B. `(pi)/(2)`
C. `(pi)/(3)`
D. `pi`

Answer

C

Explanation

`x_(1)= A sin (omega t + pi//6), x_(2) = A sin (omega t + pi//2)`
`:.` Phase difference `(pi)/(2) - (pi)/(6) = (pi)/(3)`