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A wave of frequency 500 Hz has velocity ...

A wave of frequency 500 Hz has velocity 360 m/sec. The distance between two nearest points `60^(@)` out of phase, is

A

3 cm

B

6 cm

C

12 cm

D

24 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda = (V)/(n) = (360 xx 100)/(500) = 72 cm`
Path diff. = `(lamda)/(2pi)` (Phase diff). `= (72)/(2pi) xx (pi)/(3) = 12 cm`
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