In a medium, the phase difference between two particles separated by a distance x is `(pi)/(6)`. If the frequency of the oscillation is 25 Hz and the velocity of propagation of the wave is 100 m/s then the value of x is equal to

Options

A. `(1)/(3) m`
B. `(1)/(4)m`
C. `(1)/(6)m`
D. `(1)/(8)m`

Answer

A

Explanation

`lamda = (V)/(n) = (100)/(25) = 4 m` …(1)
and Phase difference `= (2pi)/(lamda)` (Path diff)
`:. (pi)/(6) = (2pi x)/(4) " " :. 4 = 12x`…(2)
`:. x = (1)/(3) m`