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The phase difference between two points ...

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is `90^(@)` . Then the velocity of wave will be

A

256 m/s

B

384 m/s

C

512 m/s

D

700 m/s

Text Solution

Verified by Experts

The correct Answer is:
B
Phase difference `= (2pi)/(lamda)` (Path diff.)
`:. (pi)/(2) = (2pi)/(lamda) xx 0.8 :. lamda = 3.2 m`
`V = n lamda = 120 xx 3.2 = 384m//s`
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