In a simple harmonic progressive wave, the maximum particle velocity is twice the wave velocity. If `lamda` is the wavelength, then its amplitude is given by

Options

A. `(lamda)/(pi)`
B. `(2lamda)/(pi)`
C. `(lamda)/(2pi)`
D. `(2pi)/(lamda)`

Answer

A

Explanation

Max. particle velocity = 2 (Wave velocity)
`:. A omega = 2n lamda " " :. 2pi n A = 2n lamda`
`:. A (2n lamda)/(2pi n) = (lamda)/(pi)`