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The equation of a transverse wave along ...

The equation of a transverse wave along a stretched string is given by
`y = 15 sin 2pi ((t)/(0.04) - (x)/(40)) cm`.
The velocity of the wave is

A

10 m/s

B

5 m/s

C

15 m/s

D

20 m/s

Text Solution

Verified by Experts

The correct Answer is:
A
`y = 15 sin 2pi [(t)/(0.04) - (x)/(40)]`
Comparing with `y = A sin 2pi ((t)/(T) - (x)/(lamda))`
we get `lamda= 40 cm, T = 0.04 :. n = 25 Hz`
`:. v = n lamda = 40 xx 25 = 1000 cm//s = 10 m//s`
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