A wave equation which gives the displacement along the y direction is given by `y=10^(-4)sin(60t+2x)`, where x and y are in meters and t is time in seconds This represents a wave

Options

A. travelling with a velocity 30 m/s in the -ve direction of X axis
B. of wavelength `(pi)/(2) m`
C. of amplitude `10^(-4) cm`
D. of frequency `30 Hz`

Answer

A

Explanation

Comparing with the standard equation
`y = A sin(omega t + Kx)`
We get `A = 10^(-4) m, omega = 60` rad/s and K = 2m
`:. f = (omega)/(2pi) = (60)/(2pi) = (30)/(2pi) Hz`
`lamda = (2pi)/(K) = (2pi)/(2) = pi m`
and `v = flamda = (30)/(pi) xx pi = 30 m//s`
Similarly the wave is travelling in the -ve X direction as 60 and 2x have the same sign. Thus (a) is the correct choice