The displacement y of a wave travelling in the x-direction is given by
`y = 10^(-4) sin (600t - 2x + (pi)/(3)) m`
Where x is expressed in metre and t in seconds. The speed of the wave motion in m/s is

Options

A. 200
B. 1200
C. 600
D. 300

Answer

D

Explanation

`y = 10^(-4) sin(600 t - 2x + (pi)/(3)) m`
In the general equation `y = A sin(omega t - Kx)`. We consider that the initial phase `phi = 0`. If there is an initial phase `phi`, then the equation becomes
`y = A sin(omega t - Kx + phi)`….(2)
Comparing (1) and (2), we find that
`omega = 600` vib/sec and K = 2m
`:. v = (omega)/(K) = (600)/(2) = 300 m//s`
[Note : `(omega)/(K) = (2pi n)/(2pi //lamda) = n lamda = v`]