Home
Class 12
PHYSICS
A tuning fork of unknown frequency x, pr...

A tuning fork of unknown frequency x, produces 5 beats per second with a tuning fork of frequency of 250 Hz. The produces 10 beats/second with another tuning fork frequency 265 Hz. The unknow frequency is

A

245 Hz

B

255 Hz

C

275 Hz

D

270 Hz

Text Solution

AI Generated Solution

The correct Answer is:
To find the unknown frequency \( x \) of the tuning fork, we can use the information provided about the beats produced with two different tuning forks. Here’s a step-by-step solution: ### Step 1: Understand the concept of beats When two tuning forks of different frequencies are sounded together, they produce beats. The number of beats per second is equal to the absolute difference between their frequencies. ### Step 2: Set up the equations based on the given information 1. The first tuning fork has a frequency of 250 Hz and produces 5 beats per second with the unknown frequency \( x \). This gives us the equation: \[ |x - 250| = 5 \] This can lead to two possible equations: \[ x - 250 = 5 \quad \text{(Equation 1)} \] or \[ 250 - x = 5 \quad \text{(Equation 2)} \] 2. The second tuning fork has a frequency of 265 Hz and produces 10 beats per second with the unknown frequency \( x \). This gives us the equation: \[ |x - 265| = 10 \] This can also lead to two possible equations: \[ x - 265 = 10 \quad \text{(Equation 3)} \] or \[ 265 - x = 10 \quad \text{(Equation 4)} \] ### Step 3: Solve the equations **From Equation 1:** \[ x - 250 = 5 \implies x = 255 \quad \text{(Solution A)} \] **From Equation 2:** \[ 250 - x = 5 \implies x = 245 \quad \text{(Solution B)} \] **From Equation 3:** \[ x - 265 = 10 \implies x = 275 \quad \text{(Solution C)} \] **From Equation 4:** \[ 265 - x = 10 \implies x = 255 \quad \text{(Solution D)} \] ### Step 4: Analyze the solutions Now, we have the possible values for \( x \): - From Equation 1: \( x = 255 \) - From Equation 2: \( x = 245 \) - From Equation 3: \( x = 275 \) - From Equation 4: \( x = 255 \) ### Step 5: Check for consistency - If \( x = 255 \): - For 250 Hz: \( |255 - 250| = 5 \) (correct) - For 265 Hz: \( |255 - 265| = 10 \) (correct) - If \( x = 245 \): - For 250 Hz: \( |245 - 250| = 5 \) (correct) - For 265 Hz: \( |245 - 265| = 20 \) (incorrect) - If \( x = 275 \): - For 250 Hz: \( |275 - 250| = 25 \) (incorrect) ### Conclusion The only consistent solution is \( x = 255 \) Hz. Thus, the unknown frequency is: \[ \boxed{255 \text{ Hz}} \]

To find the unknown frequency \( x \) of the tuning fork, we can use the information provided about the beats produced with two different tuning forks. Here’s a step-by-step solution: ### Step 1: Understand the concept of beats When two tuning forks of different frequencies are sounded together, they produce beats. The number of beats per second is equal to the absolute difference between their frequencies. ### Step 2: Set up the equations based on the given information 1. The first tuning fork has a frequency of 250 Hz and produces 5 beats per second with the unknown frequency \( x \). This gives us the equation: \[ ...
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    MARVEL PUBLICATION|Exercise Test your grasp|15 Videos
  • SURFACE TENSION

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (TEST YOUR GRASP )|10 Videos
  • WAVE THEORY OF LIGHT AND POLARISATION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP -10|15 Videos

Similar Questions

Explore conceptually related problems

A tuning fork A produces 5 beats/sec with another tuning fork B of frequency 256 Hz. If tuning fork A produces 1 beats/sec with some other tuning fork C of frequency 250 Hz, then calculate the frequency of fork A.

A tuning fork 'P' of frequency 280Hz produces 6 beats/s with unknown tuning fork 'Q'

A tuning fork of unknown frequency produces 4 beats per second when sounded with another tuning fork of frequency 254 Hz. It gives the same number of beats per second when unknown tuning fork loaded with wax . The unknown frequency before loading with wax is

A tuning fork of frequency 100 when sounded together with another tuning fork of unknown frequency produces 2 beats per second. On loading the tuning fork whose frequency is not known and sounded together with a tuning fork of frequency 100 produces one beat, then the frequency of the other tuning fork is

A tuning fork of unknown frequency gives 4beats with a tuning fork of frequency 310 Hz. It gives the same number of beats on filing. Find the unknown frequency.

A tuning fork when sounded with tuning fork of frequency 256 produces 4 beats//sec and when sounded with another of frequency 250 produces 2 beats//sec . The frequency of the fork is -

A tuning fork A of unknown frequency produces 5 beats/s with a fork of known frequency 340 Hz. When fork A is filed, the beat frequency decreases to 2 beats/s. What is the frequency of fork A ?

If a tuning fork of frequency 512Hz is sounded with a vibrating string of frequency 505.5Hz the beats produced per sec will be

MARVEL PUBLICATION-WAVE MOTION-Test your grasp
  1. A tuning fork of unknown frequency x, produces 5 beats per second with...

    Text Solution

    |

  2. In a sinusoidal wave, the time required by a particular particle to mo...

    Text Solution

    |

  3. A longitudinal wave in air is travelling towards the closed base of me...

    Text Solution

    |

  4. If the amplitude of a wave at a distance r from a point source is A, t...

    Text Solution

    |

  5. The equation of a progressive wave is given by y = 5 sin [pi ((t)/(5...

    Text Solution

    |

  6. A simple harmonic wave is represent by the relation y(x,t)=a(0) sin ...

    Text Solution

    |

  7. Two waves of equal amplitude when superposed, give a resultant wave ha...

    Text Solution

    |

  8. A set of 11 tuning forks is arranged in the ascending order of frequen...

    Text Solution

    |

  9. An unknown frequency x produces 8 beats per seconds with a freuquency ...

    Text Solution

    |

  10. Two sound waves of wavelength (92)/(147) m and (92)/(149)m produce 8 b...

    Text Solution

    |

  11. Wavelengths of two sound notes in air are (80)/(177)m and (80)/(175)m ...

    Text Solution

    |

  12. A whistle revolves in a circle with an angular speed of 20 rad//sec us...

    Text Solution

    |

  13. An observer moves towards a stationary source of sound, with a veloci...

    Text Solution

    |

  14. Two sources A and B are sounding notes of frequency 680 Hz. A listener...

    Text Solution

    |

  15. A man is watching two trains, one leaving and the other coming in with...

    Text Solution

    |

  16. A tuning fork A having a frequency of 300 Hz is sounded together with ...

    Text Solution

    |