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A standing wave is given by y=5"sin" (pi...

A standing wave is given by `y=5"sin" (pi x)/(20) cos 40 pit`, where x and y are in cm and t is in second. What is the minimum distance between a node and the adjacent antinode ?

A

5 cm

B

`7.5 cm`

C

`10 cm`

D

15 cm

Text Solution

Verified by Experts

The correct Answer is:
C
` y = 5 sin ((pi x)/20) cos 40 pi t`
Comparing with ` y = 2a sin (Kx) cos ( omega t), ` we get,
` K = pi/20 " but " K = (2 pi)/lambda = pi/20`
` :. lambda = 40 ` cm
` :. ` Distance between a node and antinode ` lambda/4 = 10` cm
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