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A stretched string is in resonance with...

A stretched string is in resonance with a tuning fork of frequency 250 Hz. If the distance between two consecutive antinodes on the string is 5, then the velocity of the progressive wave in the string is

A

`10 m//s`

B

`15 m//s`

C

`20 m//s`

D

`25 m//s`

Text Solution

Verified by Experts

The correct Answer is:
D
Distance between two consecutive antinodes ` = lambda/2 = 5`
` :. lambda = 10 cm " " :. V = 250 xx 0.1 = 25` m/s.
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