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If the tension and diameter of a sonomet...

If the tension and diameter of a sonometer wire of fundamental frequency `n` are doubled and density is halved then its fundamental frequency will become

A

2n

B

n

C

`n/sqrt2`

D

`3n `

Text Solution

Verified by Experts

The correct Answer is:
B

`n = 1/(2L) sqrt(T/(pi r^(2) rho)) :. n_(2)/n_(1) = sqrt(T_(2)/T_(1) xx (r_(1)/r_(2))^(2) xx rho_(1)/rho_(2))`
` = sqrt( 2 xx 1/4 xx 2/1 ) = 1 :. n_(2) = n_(1) `
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