An open organ pipe has a length /and diameter d . If the velocity of sound in air is v, what is the fundamnetal frequency of the pipe when the end correction is spplied ?

Options

A. `v (2 l + 1 . 2d) ^(-1) `
B. `v ( 2 l + 0.6 d)^(-1) `
C. ` v ( 2 l + 0.3d) ^(-1) `
D. ` v ( l + 0.6d)^(-1) `

Answer

A

Explanation

For the open organ pipe, corrected length with end correction is ` l+ 0.6d = L `
and the fundamental frequency `n = V/(2L) = v/([l + 0.6d]) `
` :. n = v/(2l + 0.3 d) = v (2l + 0.3 d)^(-1)`