When the tuning fork in Melde's experime...

When the tuning fork in Melde's experiment is arranged in parallel position, the string vibrates with a fundamental frequency of 80Hz. The frequency of the runing fork is

80 Hz

160 Hz

40 Hz

240 Hz

Text Solution

Verified by Experts

The correct Answer is:

Frequency of the fork ` = 2n = 160` Hz

Topper's Solved these Questions

STATIONARY WAVES
MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (GRAPHICAL )|1 Videos
STATIONARY WAVES
MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (FROM PREVIOUS EXAMS)|11 Videos
STATIONARY WAVES
MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (HIGHER LEVEL)|75 Videos
SEMICONDUCTORS
MARVEL PUBLICATION|Exercise MCQs|261 Videos
SURFACE TENSION
MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS . (TEST YOUR GRASP )|10 Videos

Similar Questions

Explore conceptually related problems

To reduce the frequency of a tuning fork –

The frequency of vibrating string, in melde's experiment in parallel position is equal to

A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

In Melde's experiment , when the tuning fork is set in parallel position, the frequency of the string (n) and the frequency of the tuning fork (N) are related as

In parallel position of melde's experiment, string vibrates

In Melde's experiment, the tuning fork was arranged in parallel position and the vibrating length of string was 0.8m. Upon setting the tuning fork into vibration, four loops were formed along the string. If the linear density of the string is 0.5 mg/cm and the frequency of the tuning fork is 96Hz, then tension in the string will be

A tuning fork of frequency 100 when sounded together with another tuning fork of unknown frequency produces 2 beats per second. On loading the tuning fork whose frequency is not known and sounded together with a tuning fork of frequency 100 produces one beat, then the frequency of the other tuning fork is

In melde's experiment, the tuning fork was arranged in parallel position and the string was stretched by a weight of 4xx10^(-3) kg and mass per unit length of the string is 9.8xx10^(-5) kg//m . If 4 loops were formed on a length 80cm of the string, then the frequency of the fork will be

MARVEL PUBLICATION-STATIONARY WAVES-MULTIPLE CHOICE QUESTIONS (STANDARD LEVEL )

In Melde's experiment, when a tuning fork vibrates in parallel mode, 4...
Text Solution
|
In Melde's experiment , when the tuning fork is set in parallel positi...
Text Solution
|
When the tuning fork in Melde's experiment is arranged in parallel pos...
Text Solution
|
Transverse position in Melde's experiment is changed to parallel posit...
Text Solution
|
A chord attached about an end to a vibrating fork divides it into 6 lo...
Text Solution
|
In Melde's experiment , 4 loops were formed when the string was strete...
Text Solution
|
If instead of water, the resonance tube is filled with a liquid of den...
Text Solution
|
In a resonance tube experiment, a tuning fork resonates with an air ...
Text Solution
|
In a resonance tube experiment, the first and second resonace occur, w...
Text Solution
|
If a resonace tube gives two consecutive resonances at the length of ...
Text Solution
|
An organ pipe open at one end is vibrating in first overtone and is in...
Text Solution
|
A long glass tube is held vertically in water . A tuning fork is struc...
Text Solution
|
In the resonance tube experiment , maximum sound is heard, when the le...
Text Solution
|
In a resonance tube experiment the difference between the first and se...
Text Solution
|
A tuning fork is in unison with an air column of length 20 cm in a r...
Text Solution
|
In a resonace tube experiment, the first resonance is obtained when th...
Text Solution
|
The end correction of a resonance column in resonance tube experiment ...
Text Solution
|
In a resonace tube experiment the lengths of the air columns for the f...
Text Solution
|
For a resonace tube, the air columns for the first and second resonace...
Text Solution
|
In a resonace tube, the first resonating length is 0.2 m and the secon...
Text Solution
|