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The end correction of a resonance colume...

The end correction of a resonance colume is 1.0 cm.
If the shortest length resonating with the tuning fork is
`15.0` cm the next resonating length will be

A

35 cm

B

40 cm

C

47 cm

D

64 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda = 4 (L + 1) = 4 (15 + 1) = 64`
For the second resonance,
`l' = (3lambda)/4 = (3 xx 64)/4 = 48 ` cm
` :. ` Second resonating length ' L' - end correction
` = 48 - 1 = 47` cm
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