A point P is at a distance r from a point charge q. if at point P, the electric potential is 300 V, and the electric field intensity is 75 V/m, then the distance of P from the point charge is

Options

A. 2 m
B. 4 m
C. 8 m
D. 10 m

Answer

B

Explanation

`E=(1)/(4piepsi_(0))xx(q)/(r^(2)) and V=(1)/(4piepsi_(0))(q)/(r)`
`therefore (V)/(E)=(q//r)/(q//r^(2))=r there fore r=(300v)/(75v//m)=4m`