A charge of 12 `muC` is kept inside a closed surface. What is the flux flowing through a portion of the surface, which subtends a solid angle of `pi` at the point where are charge is situated?

Options

A. `(6xx10^(-6))/(epsi_(0))`volt-m
B. `(2xx10^(-6))/(epsi_(0))`volt-m
C. `(3xx10^(-6))/(epsi_(0))`volt-m
D. `(4xx10^(-6))/(epsi_(0))`volt-m

Answer

C

Explanation

Flux through the portion`=(pi)/(4pi)[(q)/(epsi_(0))]`
`=(12xx10^(-6))/(4epsi_(0))=(3xx10^(-6))/(epsi_(0))`