The electric flux for Gaussian surface `A` that enclose the charge particles in free space is (given `q_(1)= -14nC,q_(2)= 78.85nC,q_(3)= -56nC)`

Options

A. `10^(3)Nm^(2)//C`
B. `10^(3)C//Nm^(2)`
C. `632xx10^(3)Nm^(2)//C`
D. `632xx10^(3)C//Nm^(2)`

Answer

A

Explanation

Net charge enclosed by the surface A
`=[-14+78.85-56]xx10^-9" "(because 1nC=10^(-9)C)`
`=8.85xx10^(-9)C`
Gaussian surface B does not have a charge.
By gauss's law,
`phi=(q_("net"))/(epsi_(0))=(8.85xx10^(-9))/(8.85xx10^(-12))=10^(3)Nm^(2)//C`