What is the flux through a cube of side `'a'` if a point charge of `q` is at one of its corner :

Options

A. `(2q)/(epsi_(0))`
B. `(q)/(8epsi_(0))`
C. `(q)/(epsi_(0))`
D. `(q)/(2epsi_(0))6a^(2)`

Answer

B

Explanation

For this we have to imagine that the charge q is placed at the centre of a large cube which is formed by 8 identical cubges, proper arranged.
by gauss's theorem,
`therefore`Total flux `phi` through the bigger cube`=(q)/(epsi_(0))`
`therefore`Flux through one small cube`=(q)/(8epsi_(0))`