A 100 `muF` capacitor is to have an energy content of 50 J to operate a flash bulb. The voltage required to charge the capacitor is

Options

A. 1000 V
B. 2000 V
C. 500 V
D. 250 V

Answer

A

Explanation

`E=(1)/(2)CV^(2)" "therefore V^(2)=(2E)/(C)=(2xx50)/(100xx10^(-6))=10^(6)`
`therefore V=10^(3)=1000V`