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A 4muF capacitor is charged to 4000 V, i...

A `4muF` capacitor is charged to 4000 V, if the plates joined through a resistanceof 4`Komega`, then the heat produced in the resistance will be

A

0.08 J

B

0.16 J

C

0.32 J

D

0.4 J

Text Solution

Verified by Experts

The correct Answer is:
C
Heat produced=energy stored
`=(1)/(2)CV^(2)=(1)/(2)xx4xx10^(-6)xx(400)^(2)=0.32J`
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