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The potentials of the two plates of capa...

The potentials of the two plates of capacitor are `+10V` and `-10 V`. The charge on one of the plate is `40 C`. The capacitance of the capacitor is

A

`4muF`

B

`2muF`

C

`0.5F`

D

`0.4F`

Text Solution

Verified by Experts

The correct Answer is:
B
`C=(Q)/(V_(A)-V_(B))=(40xx10^(-6))/(20)=2muF`
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