A parallel plate air capacitor is charged to a potential difference of `V` volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an isulating handle. As a result the potential difference between the plates

Options

A. `(V)/(sqrt(3))`
B. `3V`
C. `(V)/(3)`
D. `sqrt(3)V`

Answer

B

Explanation

When the distance is increased to 3 times, capacity becomes `(C)/(3)(C=(1)/(d))` but the cahrge remains constant.
`therefore V'=(q)/(C')=(q)/(C//3)=(3q)/(C)=3V`