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The capacity of a paralel plate condense...

The capacity of a paralel plate condenser is `12muF`. What is its new capacity if the separation between the plates is doubled and the area is halved?

A

`1.5muF`

B

`3muF`

C

`6muF`

D

`8muF`

Text Solution

Verified by Experts

The correct Answer is:
B
`(C_(2))/(C_(1))=(KA_(2)epsi_(0))/(d_(2))xx(d_(1))/(KA_(1)epsi_(0))=(1)/(2)xx(1)/(2)=(1)/(4)`
`therefore C_(2)=(C_(1))/(4)=3muF`
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