A 80 pF capacitor is charged to 15 V by connecting it to a battery. How many electrons are transferred from one plate to another?

Options

A. `7.5xx10^(9)`
B. `6xx10^(9)`
C. `5xx10^(8)`
D. `9xx10^(8)`

Answer

A

Explanation

`q=CV=80xx10^(-12)xx15=1200xx10^(-12)=1.2xx10^(-9)C`
`therefore`Number of electrons `n=(q)/(c)=(1.2xx10^(-9))/(1.6xx10^(-19))`
`=0.75xx10^(10)=7.5xx10^(9)`