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What potential difference should be appl...

What potential difference should be applied to `2muF` capacitor to get an energy of `10^(-2)` joule?

A

10 V

B

50 V

C

75 V

D

100 V

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(1)/(2)Cv^(2)`
`therefore V=sqrt((2E)/(C))=sqrt((2xx10^(-2))/(2xx10^(-6)))=100V`
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