A 500 `muF` uncharged capacitor is cahrged at a steady rate of 100 `muC`second.t he potential difference across the capacitor will be 10 V after time t equal to

Options

A. 5 sec
B. 25 sec
C. 20 sec
D. 50 sec

Answer

D

Explanation

When the potential becomes 10 V, the charge Q is given by
`Q=CV=500xx10^(-6)xx10=5000xx10^(-6)C`
`therefore`Rate of charging`=100xx10^(-6)C//s`
`therefore`Time required`=(5000xx10^(-6))/(100xx10^(-6))=50s`