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A parallel plate condenser with oil (die...

A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes

A

`C/2`

B

`(C)/(sqrt(2))`

C

`2C`

D

`sqrt(2C)`

Text Solution

Verified by Experts

The correct Answer is:
A

`C'=(KA epsi_(0))/(d)=(2A epsi_(0))/(d)`
When oil is removed, the capacitance becomes`C'=(Aepsi_(0))/(d)`
`therefore =(C')/(C)=(Aepsi_(0))/(d)xx(d)/(2A epsi_(0))=(1)/(2)" "therefore C'=(C)/(2)`
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