If the distance between the plates of parallel plate capacitor is halved and the dielectric constant of dielectric is doubled, then its capacity will

Options

A. increase by 2 times
B. remain the sae
C. increase by 4 times
D. increase by 16 times

Answer

C

Explanation

`C=(KA epsi_(0))/(d)" i.e. "Cprop(K)/(d)`
`(C_(2))/(C_(1))=(K_(2))/(K_(1))xx(d_(1))/(d_(2))=2xx2=4`
`therefore C_(2)=4C_(1)`