A capacitor of capacity 10 `muF` is charged to a potential of 10000 V and a wire is stretched by 0.2 m by a force of 5000 N. the ratio of the potential energies stored in them will be

Options

A. 1
B. 500
C. 0.002
D. 0.0001

Answer

A

Explanation

Ratio is `((1)/(2)CV^(2))/((1)/(2)Fxxe)=(CV^(2))/(Fe)`
`=(10xx10^(-6)xx(10^(4))^(2))/(5000xx0.2)=1`