A fully charged capacitor has a capacitance 'C'. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity 's' and mass 'm'. If the temperature of the block is raised by 'DeltaT', the potential difference 'V' across the capacitance is

Options

A. `sqrt((2mCDeltaT)/(s))`
B. `(mCDeltaT)/(s)`
C. `sqrt((2msDeltaT)/(C))`
D. `(msDeltaT)/(C)`

Answer

C

Explanation

The energy stored in the capacitor`=(1)/(2)CV^(2)`
It is lost in the form of heat energy.
Heat required to raise the temperature of the block=msdIT
`therefore (1)/(2)CV^(2)=msdT" "therefore V=sqrt((2msdT)/(C))`
(we assume that both H and W are expressed in the same units. otherwise we have to use W=JH).