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A parallel plate capacitor is connected ...

A parallel plate capacitor is connected to a battery. The plates are pulled apart with uniform speed. If x is the separation between the plates, then the rate of change of electrostatic energy of the capacitor is proportional to

A

`x^(-2)`

B

`x`

C

`x^(-1)`

D

`x^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Energy `(U)=(1)/(2)CV^(2)=(1)/(2)((epsi_(0)A)/(x))V^(2)`
`therefore (dU)/(dt)=(1)/(2)epsi_(0)AV^(2)(-(1)/(x^(2))(dx)/(dt))` but `(dx)/(dt)`=velocity (v')
`=-((1)/(2)epsi_(0)AV^(2)V')(1)/(x^(2))`
`therefore (dU)/(dt)prop x^(-2)`
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