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The capacitance of a parallel plate cond...

The capacitance of a parallel plate condenser with a separation of 4 mm between the plates is `7muF`. If a mica sheet (K=6) of thickness 2 mm and of the same area is introduced betwenn the plates, its capacitance will be

A

`6muF`

B

`9muF`

C

`12muF`

D

`15muF`

Text Solution

Verified by Experts

The correct Answer is:
C
`C_(1)=(epsi_(0)A)/(d)=7muF`
`C_(2)=(epsi_(0)A)/((d)/(2)+(d)/(2xx6))=(epsi_(0)A)/((7)/(12)d)=(epsi_(0)A)/(d)xx(12)/(7)`
`therefore C_(2)=7xx(12)/(7)=12muF`
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