The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

Options

A. `(epsi_(0)A)/(d-x(1-(1)/(K)))`
B. `(epsi_(0)A)/(d+x(1-(1)/(K)))`
C. `(epsi_(0)A)/(d+x(1+(1)/(K)))`
D. `(epsi_(0)A)/(d-x(1+(2)/(K)))`

Answer

A

Explanation

`C=(epsi_(0)A)/((d-x)+(x)/(K))=(epsi_(0)A)/(d-x(1-(1)/(K)))`