Five capacitors each of capacity C are joined as shown in the following figure. If theire resultant capacity `C_(R)=2muF`, then the capacity of each capacitor is

Options

A. `5muF`
B. `20muF`
C. `10muF`
D. `4muF`

Answer

C

Explanation

They are joined in series
`(1)/(C_(S))=(1)/(c)+(1)/(c)+(1)/(c)+(1)/(c)+(1)/(c)=(5)/(c)=(1)/(2)`
`therefore C=10muF`