You are given three condensers, each of capacitance `30muF` and a battery of emmf 200 V. they can be joined in series or in parallel. Which arrangement of the condensers will give the minimum energy?

Options

A. All in series
B. All in parallel
C. Two in series and the third in parallel
D. Two in parallel and the third in series

Answer

A

Explanation

`C_(p)=30+30+30=90muF`
`(1)/(C_(S))=(1)/(30)+(1)/(30)+(1)/(30)=(3)/(30)=(1)/(10)`
`therefore C_(S)=10muF,C_(S) lt C_(p)" as "E=(1)/(2)CV^(2)`
`therefore`The energy will be minimum when they are joined in series.