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A capacitor or capacitance C(1) is char...

A capacitor or capacitance `C_(1)` is charge to a potential V and then connected in parallel to an uncharged capacitor of capacitance `C_(2)`. The fianl potential difference across each capacitor will be

A

`(C_(1)V)/(C_(1)+C_(2))`

B

`(C_(2)V)/(C_(1)+C_(2))`

C

`(C_(1)+C_(2))/(C_(1)V)`

D

`(C_(1)+C_(2))/(C_(2)V)`

Text Solution

Verified by Experts

The correct Answer is:
A

The charge remains constant in the first and second case.
`therefore Q=C_(1)V=C'V'` where `C'=C_(1)+C_(2)`
`therefore (C_(1)+C_(2))V'=C_(1)V`
`therefore V'=(C_(1)V)/(C_(1)+C_(2))`
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