If there are `n` capacitors each of capacitance `C` in series combination connected to a `V` volt source, then the energy stored in each capacitor is equal to :

Options

A. `nCV^(2)`
B. `(1)/(2)nCV^(2)`
C. `(1)/(4)nCV^(2)`
D. `(1)/(2n)CV^(2)`

Answer

D

Explanation

For series capacitors
`(1)/(C_(S))=(1)/(C)+(1)/(C)+ . . .=(n)/(C)" "therefore C_(S)=(C)/(n)`
Energy stored in all capacitors
`=(1)/(2)C_(S)V^(2)=(1)/(2)(C)/(n)V^(2)=(1)/(2n)CV^(2)`