4 capacitors each of capacity `2muF` are joined as shown in the figure. What is the capacity between the points A and B.

Options

A. `1/(2)muF`
B. `(2)/(9)muF`
C. `(4)/(5)muF`
D. `(7)/(9)muF`

Answer

C

Explanation

`C_(2) and C_(3)` are in parallel,
`therefore`Theire resultant capacity`=4muF`
`therefore`The three capacitors of `2muF`,`4muF` and `2muF` are in series.
`therefore (1)/(C_(S))=(1)/(2)+(1)/(4)+(1)/(2)=(9)/(4)`
`C_(S)=(4)/(9)muF`