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Three capacitors each of capacity C are ...

Three capacitors each of capacity C are first joined in parallel and then in series. It is found that the difference in their effective capacities when joined in parallel and series respectively is `16muF`. What is the capacitance of each capacitor?

A

`3muF`

B

`4muF`

C

`5muF`

D

`6muF`

Text Solution

Verified by Experts

The correct Answer is:
D
First case C=3C
Second case, the resultant capacity=C/3
`therefore 3C-(C)/(3)=16muF " "therefore 8C=48muF" "therefore C=6muF`
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