Two capacitors `A` and `B` are connected in series with a battery as shown in the figure. When the switch `S` is closed and the two capacitors get charged fully, then

Options

A. the ratio of electrical energies stored in A and B is 2:3
B. the potential difference across the plates of A is 6V and across the plates of B is 4V
C. the ratio of charge on A and B is 3:2
D. the potential difference across the plates of A is 4V and across the plates of B is 6V

Answer

B

Explanation

When A and B are joined in series, the same charge is developed across each.
`therefore Q=C_(1)V_(1)=C_(2)V_(2)`
`therefore (V_(1))/(V_(2))=(C_(2))/(C_(1))=(3)/(2)" "therefore V_(1)=(3)/(2)V_(2)`
`therefore (3)/(2)V_(2)+V_(2)=10" "therefore V_(2)=4V and V_(1)=6V`
`therefore`P.D. across A=6V and P.D. across B=4V