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Two capacitors having capacitances C(1) ...

Two capacitors having capacitances `C_(1)` and `C_(2)` are charged with 120 V and 200 V batteries respectively. When they are connected in parallel now, it is found that the potential on each one of them is zero. Then,

A

`9C_(1)=4C_(2)`

B

`5C_(1)=3C_(2)`

C

`3C_(1)=5C_(2)`

D

`5C_(1)=-3C_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`C=(Q)/(V)" "therefore Q_(1)=120C_(1),Q_(2)=200C_(2)`
since the potential becomes zero, the net charge on the combination must be zero.
`therefore Q_(1)+Q_(2)=0" "therefore 120C_(1)=-200C_(2)" "therefore 3C_(1)=-5C_(2)`.
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