The difference in the effective capacities of two similar capacitors when joined in series and then in parallel is `6muF`. The capacity of each capacitor is

Options

A. `2muF`
B. `4muF`
C. `8muF`
D. `16muF`

Answer

B

Explanation

When they are joined in parallel, `C_(P)=C+C=2C`
and when in series,
`(1)/(C_(S))=(1)/(C)+(1)/(C)=(2)/(C) or C_(S)=(C)/(2)`
`therefore 2C-(C)/(2)=6muF` (given)
`therefore (3C)/(2)=6" "therefore C=4muF`