n capacitors each of capacity C are joined in parallel. If they are connected to a source of V volts, then the energy stored in the capacitor is

Options

A. `CV^(2)`
B. `(1)/(2n)CV^(2)`
C. `(1)/(2)nCV^(2)`
D. `(1)/(2)(n)/(C)V^(2)`

Answer

C

Explanation

Resultant capacity `C'=nC`
`therefore E=(1)/(2)C'V^(2)=(1)/(2)nCV^(2)`