A particle of mass m and charge q is placed at rest in a uniform electric field E and then released, the kinetic energy attained by the particle after moving a distance y will be

Options

A. `qEy^(2)`
B. `qE^(2)y`
C. `qEy`
D. `q^(2)Ey`

Answer

C

Explanation

`because E=(F)/(q)" "therefore F=Eq`
`therefore `K.E. acquired by the particle
=Work done=`Fxxs=Eqy`