A network of 4 capacitors, each of `6muF` is connected to a 240 V supply as shown in the figure. What are the charges on the capacitor `C_(2) and C_(4)` ?

Options

A. 1.44 mC and 0.48 mC
B. 0.48 mC and 1.44 mC
C. 14.4 mC and 4.8 mC
D. 4.8 mC and 14.4 mC

Answer

B

Explanation

The capacitors `C_(1),C_(2) and C_(3)` are in series,
`thereforeP.D.` across each capacitor is `(V)/(3)=(240)/(3)=80V`
Each capacitor has the same charge
`therefore`Charge on `C_(2)` in `Q_(2)`
`=C_(2)xx(V)/(3)=6xx10^(-6)xx80`
`=480xx10^(-6)C=0.48xx10^(-3)C=0.48mC`
and charge on `C_(4)` is `Q_(4)`
`=C_(4)xxV=6xx10^(-6)xx240=1.44xx10^(-1)C=1.44mC`