When threee capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series withs its combination . The resultant capacity is `3.75 muF`. The capacity of each capacitor is

Options

A. `5muF`
B. `6muF`
C. `7muF`
D. `8muF`

Answer

A

Explanation

For 3 parallel capacitors, `C_(P)=3C`
and 3C and C are joined in series,
`therefore C_(eq)=(3CxxC)/(3C+C)=(3C^(2))/(4C)=(3C)/(4)`
and `C_(eq)=3.75muF`
`therefore C=(4xxC_(eq))/(3)=(4xx3.75)/(3)=4xx1.25=5muF`