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An infinite line charge produces an electric field of `9xx10^(4)N//C` at a distance of 2 cm. what is the linear charge density?

A

`10^(-5)C//m`

B

`10^(-6)C//m`

C

`10^(-7)C//m`

D

`10^(-8)C//m`

Text Solution

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The correct Answer is:
To find the linear charge density (λ) of an infinite line charge that produces an electric field (E) of \(9 \times 10^4 \, \text{N/C}\) at a distance (r) of 2 cm, we can use the formula for the electric field due to an infinite line charge: \[ E = \frac{\lambda}{2 \pi \epsilon_0 r} \] Where: - \(E\) is the electric field, - \(\lambda\) is the linear charge density, - \(\epsilon_0\) is the permittivity of free space (\(8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2\)), - \(r\) is the distance from the line charge. ### Step 1: Convert the distance from cm to meters Given that \(r = 2 \, \text{cm}\), we convert this to meters: \[ r = 2 \, \text{cm} = 2 \times 10^{-2} \, \text{m} \] **Hint:** Always convert units to the SI system for consistency. ### Step 2: Substitute the known values into the electric field formula We can rearrange the formula to solve for \(\lambda\): \[ \lambda = E \cdot 2 \pi \epsilon_0 r \] Now substituting the known values: \[ E = 9 \times 10^4 \, \text{N/C} \] \[ \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2 \] \[ r = 2 \times 10^{-2} \, \text{m} \] ### Step 3: Calculate \(\lambda\) Now we can plug in the values into the equation: \[ \lambda = (9 \times 10^4) \cdot (2 \pi) \cdot (8.85 \times 10^{-12}) \cdot (2 \times 10^{-2}) \] Calculating step by step: 1. Calculate \(2 \pi \approx 6.2832\). 2. Calculate \(9 \times 10^4 \times 6.2832 \approx 5.654 \times 10^5\). 3. Calculate \(5.654 \times 10^5 \times 8.85 \times 10^{-12} \approx 5.007 \times 10^{-6}\). 4. Finally, multiply by \(2 \times 10^{-2}\): \[ \lambda \approx 5.007 \times 10^{-6} \times 2 \approx 1.0014 \times 10^{-5} \, \text{C/m} \] ### Step 4: Round to significant figures Rounding to significant figures, we find: \[ \lambda \approx 1.0 \times 10^{-5} \, \text{C/m} \] ### Final Answer Thus, the linear charge density is: \[ \lambda \approx 1.0 \times 10^{-7} \, \text{C/m} \] **Hint for Step 4:** When rounding, consider the significant figures based on the precision of the given values.

To find the linear charge density (λ) of an infinite line charge that produces an electric field (E) of \(9 \times 10^4 \, \text{N/C}\) at a distance (r) of 2 cm, we can use the formula for the electric field due to an infinite line charge: \[ E = \frac{\lambda}{2 \pi \epsilon_0 r} \] Where: - \(E\) is the electric field, ...
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