A capacitor of capacitance `C` is charged to a potential `V`. The flux of the electric field through a closed surface enclosing the capacitor is

Options

A. `(CV)/(epsi_(0))`
B. `(2CV)/(epsi_(0))`
C. `(CV)/(2epsi_(0))`
D. zero

Answer

D

Explanation

The net charge on the capacitor is always zero because the two plates have the charges +Q and -Q
[When we say that the charge on the capacitor is Q, we consider the magnitude of the charge].
Hence the net flux through the closed surface, enclosing the capacitor is zero. `[phi=(Q)/(epsi_(0))=0]` gauss's theorem.