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The capacity of a parallel plate condens...

The capacity of a parallel plate condenser with dielectric constant 10 is `16xx10^(-6)F`. If the dielectric is removed, then the new capacity will be

A

`1.6xx10^(-6)F`

B

`3.2xx10^(-6)F`

C

`0.8xx10^(-6)F`

D

`2xx10^(-6)F`

Text Solution

Verified by Experts

The correct Answer is:
A
`(C)/(C_(air))=K" "thereforeC_(air)=(C)/(K)`
`=(16xx10^-6)/(10)=1.6xx10^(-6)F`
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